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Simple and best practice solution for x^2y^22xy4x1=0 equation Check how easy it is, and learn it for the future Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homeworkAnswer (1 of 5) The equation \displaystyle{ (1x^2)y'' 2xy' 2y = 0 }\qquad(1) Since we have no obvious way to find any particular solution of (1) so we should try to find its general solution in the form of a power series as follows \displaystyle{ y = C_0 C_1x C_2x^2 \dots C_nx^2Steps Using the Quadratic Formula (y1) { x }^ { 2 } 2xyy1=0 ( y − 1) x 2 − 2 x y y 1 = 0 All equations of the form ax^ {2}bxc=0 can be solved using the quadratic formula \frac {b±\sqrt {b^ {2}4ac}} {2a} The quadratic formula gives two solutions, Gdz Nomer 513 Algebra 9 Klass Makarychev Mindyuk (1-x^2)y'' 2xy'=0 y1=1